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3c^2=576
We move all terms to the left:
3c^2-(576)=0
a = 3; b = 0; c = -576;
Δ = b2-4ac
Δ = 02-4·3·(-576)
Δ = 6912
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6912}=\sqrt{2304*3}=\sqrt{2304}*\sqrt{3}=48\sqrt{3}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48\sqrt{3}}{2*3}=\frac{0-48\sqrt{3}}{6} =-\frac{48\sqrt{3}}{6} =-8\sqrt{3} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48\sqrt{3}}{2*3}=\frac{0+48\sqrt{3}}{6} =\frac{48\sqrt{3}}{6} =8\sqrt{3} $
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